I have an ODDS question. and I lost my calculator?
By5 people are seated at a poker table playing Texas Holdem. your using a single deck of cards, Ace thru King no jokers. Each player is dealt 2 cards. what are the odds of one player being dealt a pair of aces and another player being dealt a pair of Kings on the first 2 cards?
Thanks
in the absence of a direct mention whether
EXACTLY one player each or AT LEAST one player each
is to get a pair of aces & a pair of kings,
i am assuming it is the latter,
as in common parlance, EXACTLY wd always be mentioned
whereas AT LEAST is often omitted
PROBABILITY of such an event occurring
= 4C2*4C2*48C2*46C2*44C2 / (52C2*50C2*48C2*46C2*44C2)
= 4C2*4C2 / (52C2*50C2)
= 36 in 1,624,350
= 6 in 270,725
so ODDS are 270,719 : 6 against





1 Comments
June 22nd, 2009 at 11:12 pm
in the absence of a direct mention whether
EXACTLY one player each or AT LEAST one player each
is to get a pair of aces & a pair of kings,
i am assuming it is the latter,
as in common parlance, EXACTLY wd always be mentioned
whereas AT LEAST is often omitted
PROBABILITY of such an event occurring
= 4C2*4C2*48C2*46C2*44C2 / (52C2*50C2*48C2*46C2*44C2)
= 4C2*4C2 / (52C2*50C2)
= 36 in 1,624,350
= 6 in 270,725
so ODDS are 270,719 : 6 against
References :