Jun
22

I have an ODDS question. and I lost my calculator?

By admin

5 people are seated at a poker table playing Texas Holdem. your using a single deck of cards, Ace thru King no jokers. Each player is dealt 2 cards. what are the odds of one player being dealt a pair of aces and another player being dealt a pair of Kings on the first 2 cards?

Thanks

in the absence of a direct mention whether
EXACTLY one player each or AT LEAST one player each
is to get a pair of aces & a pair of kings,
i am assuming it is the latter,
as in common parlance, EXACTLY wd always be mentioned
whereas AT LEAST is often omitted

PROBABILITY of such an event occurring

= 4C2*4C2*48C2*46C2*44C2 / (52C2*50C2*48C2*46C2*44C2)

= 4C2*4C2 / (52C2*50C2)

= 36 in 1,624,350

= 6 in 270,725

so ODDS are 270,719 : 6 against


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1 Comments

1

in the absence of a direct mention whether
EXACTLY one player each or AT LEAST one player each
is to get a pair of aces & a pair of kings,
i am assuming it is the latter,
as in common parlance, EXACTLY wd always be mentioned
whereas AT LEAST is often omitted

PROBABILITY of such an event occurring

= 4C2*4C2*48C2*46C2*44C2 / (52C2*50C2*48C2*46C2*44C2)

= 4C2*4C2 / (52C2*50C2)

= 36 in 1,624,350

= 6 in 270,725

so ODDS are 270,719 : 6 against
References :

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