Comments on: I have an ODDS question. and I lost my calculator? http://www.bestholdemcalculator.com/335/i-have-an-odds-question-and-i-lost-my-calculator/ Poker calculators are evolving; we review the best so you can build your bankroll! Tue, 07 Jul 2009 00:26:10 +0000 http://wordpress.org/?v=2.9.2 hourly 1 By: O'Neil http://www.bestholdemcalculator.com/335/i-have-an-odds-question-and-i-lost-my-calculator/comment-page-1/#comment-867 O'Neil Tue, 23 Jun 2009 04:12:59 +0000 http://www.bestholdemcalculator.com/335/i-have-an-odds-question-and-i-lost-my-calculator/#comment-867 in the absence of a direct mention whether EXACTLY one player each or AT LEAST one player each is to get a pair of aces & a pair of kings, i am assuming it is the latter, as in common parlance, EXACTLY wd always be mentioned whereas AT LEAST is often omitted PROBABILITY of such an event occurring = 4C2*4C2*48C2*46C2*44C2 / (52C2*50C2*48C2*46C2*44C2) = 4C2*4C2 / (52C2*50C2) = 36 in 1,624,350 = 6 in 270,725 so ODDS are 270,719 : 6 against<br><b>References : </b><br> in the absence of a direct mention whether
EXACTLY one player each or AT LEAST one player each
is to get a pair of aces & a pair of kings,
i am assuming it is the latter,
as in common parlance, EXACTLY wd always be mentioned
whereas AT LEAST is often omitted

PROBABILITY of such an event occurring

= 4C2*4C2*48C2*46C2*44C2 / (52C2*50C2*48C2*46C2*44C2)

= 4C2*4C2 / (52C2*50C2)

= 36 in 1,624,350

= 6 in 270,725

so ODDS are 270,719 : 6 against
References :

]]>